in pqr. d and e are points on side pq and pr respectively such that de|| qr. if pr = 2cm. pd= 3cm and qd = 4.5cm. then find re.
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Given :-
- DE || QR .
- PE = 2 cm.
- PD = 3 cm.
- QD = 4.5 cm.
To Find :-
- RE = ?
Solution :-
we know that,
- If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in the same ratio. { Also called BPT(Basic Proportionality Theorem) } .
since DE || QR .
so,
→ PD/DQ = PE/ER (By BPT)
putting values we get,
→ (3/4.5) = (2/RE)
→ (30/45) = (2/RE)
→ (2/3) = (2/RE)
→ RE = 3 cm (Ans.)
Learn more :-
In ABC, AD is angle bisector,
angle BAC = 111 and AB+BD=AC find the value of angle ACB=?
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