In ∆PQR, E and F are points on sides PQ and PR respectively. PQ=1.28cm, PR=2.56cm, PE=0.18cm and PF=0.36cm. Show that EF∥QR. this question is from triangles class 10 solve it quick
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Answer:
Step-by-step explanation:
this can be proved by converse of bpt theorem
for that we have to find whether EF divides sides PQ and PR in the same ratio
PE / PQ = PF / PR
0.18 / 1.28 = 0.36 / 2.56
by cross multiplication:-
0.4608 = 0.4608
Therefore, EF divides sides PQ and PR in the same ratio
so by converse of bpt, we can say that EF II QR
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