Question

In ΔPQR if angle Q is equal to 90° If 4 Sin P = 3 Cos P then find Cot P, Sin P and Sec P​

Answer 1

Answer:

 Cot P =  $\frac{4}{3\\}$ sin P = $\frac{3}{5}$ and finally sec P = $\frac{5}{4}$

Step-by-step explanation:

Hey mate here's your explanation

(Hint: these type of questions are easily solved assuming and drawing a right angled triangle)

Given,

4 sin p = 3 cos p.

by definition of cot theta.

cot theta = cos theta/sin theta

so 4/3 = cos p/sinp=cot p

therefore cot p=4/3--------(i)

Now, cot theta is also = adjecent side/opposite side.

Now QR = 3(by (i))

and PQ = 4(by (i))

and PR which is hypotenuse is 5(by pythagoras theorem)

so sin theta = opposite side/hypotenuse.

sin p =3/5

sec theta = hypotenuse/adj. side

sec p =5/4.

HOPE THIS HELPS YOU

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