in∆PQR if l(PQ)=(3x-1),(QR)=15x and l(PR)=(15x+1),then for which value of x will ∆PQR be a right angled triangle??
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12
x=0,4.......................
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sachin8555:
thanks bro
Answered by
26
by using pythagoras theorem
(PR)^2=(PQ)^2 + (QR)^2
(15x+1)^2=(3x-1)^2+(15x)^2
(225x^2+1+30x) =(9x^2+1-6x) + (225x^2)
30x=9x^2-6x
36x=9x^2
4x=x^2
x=4
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