Question

in∆PQR if l(PQ)=(3x-1),(QR)=15x and l(PR)=(15x+1),then for which value of x will ∆PQR be a right angled triangle??

Answer 1

x=0,4.......................

Answer 2

by using pythagoras theorem

(PR)^2=(PQ)^2 + (QR)^2

(15x+1)^2=(3x-1)^2+(15x)^2

(225x^2+1+30x) =(9x^2+1-6x) + (225x^2)

30x=9x^2-6x

36x=9x^2

4x=x^2

x=4