Question

IN ∆PQR, IF <P= 60 AND <Q= 80 THEN <R=.....​

Answer 1

don't understand sorry for yhat

Answer 2

IN ∆PQR, IF <P= 60 AND <Q= 80 THEN <R=

solution

<P + <Q + <R = 180

60 + 80 + <R = 180

(sum of three angles of Δ is 180)

140 + <R = 180

<R = 180- 140

<R = 40