in ∆pqr if p=100 pm bisects <p and pm perpendicular qr then find Q
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Given : ∆pqr ∠P =100°
PM bisect ∠P
PM ⊥ QR
To Find : ∠Q
Solution:
∠P =100°
PM bisect ∠P
=> ∠QPM = (1/2)∠P
=> ∠QPM = (1/2)100°
=> ∠QPM = 50°
PM ⊥ QR
=> ∠PMQ = 90°
in Δ PQM
∠QPM + ∠PMQ + ∠Q = 180°
=> 50° + 90° + ∠Q = 180°
=> ∠Q =40°
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