Question

In ∆PQR,if P=2x+10,Q=3x and R=3x-30,then find the measures of angle of ∆PQR​

Answer 1

Answer:

Given, P=2Q, 2R=3Q

let angle Q be "x"

P=2x,Q=x ,and R=(3/2)x

sum of all angles of a triangle is 180°

so 2x+x+(3÷2)x =180°

from here we get that x=40°

Q=40,P=80and R=60

Answer 2

In ∆PQR

P= 2x+10°

Q=3x°

R=3x-30°

Using Angle Sum Property (ASP)

P+Q+R=180°

2x+10+3x+3x-30=180°

2x+6x-20=180°

8x=180°+20°

8x=200°

x=200/8

x=25°

Then,

P=2x+10

=2(25)+10

=50+10

P=60°

Q=3x

=3(25)

Q=75°

R=3x-30

=3(25)-30

=75-30

R=45°