Question

in ΔPQR ,IF ∠P-∠Q=42° AND ∠Q-∠R=21° FIND∠P,∠Q AND ∠R

Answer 1

Solution :

→ ∠P - ∠Q = 42°

→ ∠P = 42 + ∠Q --------- eq1

→ ∠Q - ∠R = 21°

→ ∠R = ∠Q - 21° -------- eq2

Sum of Angle in Triangle = 180°

→ ∠P + ∠Q + ∠R = 180°

→ 42 + ∠Q + ∠Q + ∠Q - 21 = 180

→ 3∠Q = 180 - 21

→ 3∠Q = 159

→ ∠Q = 159/3

→ ∠Q = 53°

Put value of Q in eq 1 to find ∠P

→ ∠P = 42 + ∠Q

→ ∠P = 42 + 53

→ ∠P = 95°

Put value of Q in eq 2 to find ∠R

→ ∠R = ∠Q - 21°

→ ∠R = 53 - 21

→ ∠R = 32°