Question

In ∆PQR , If PQ = 10 cm and ∠R = 90⁰ , ∠Q = 30⁰ , then QR = ? *

Answer 1

Answer:

Step-by-step explanation:

By 30-60-90degree theorem

PR= 1/2× hypo=1/2×10=5cm

By Pythagoras theorem

Pq²=pr²+qr²

10²=5²+qr²

100-25=qr²

Qr²= 75

QR=5√3

Is the answer

Answer 2

Step-by-step explanation:

QR = 5√3

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