In ∆PQR,if PQ>pR and bisectors of angle Q and angle R intersect at S. show that SQ >SR.
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In triangle POQ,
PQ is greater than PR
Angle PRQ will be greater than angle PQR since the angle opp to greater side is greater and smaller side is smaller
Multiplying ½ on both sides,
½ angle PRQ is greater than ½ angle PQR
Since SQ and SR are bisectors of angle Q and R respectively,
Angle SRQ is greater than SQR,
Since side opp to greater angle is greater, hence,
SQ is greater than SR
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