Question

In ∆PQR,if the measures of Q and R are 100°and45°,respectively,find the measure of P.

Answer 1

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Here's ur answer dear:-)
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Given , In ∆PQR, the measures of Q and R are 100°and45° respectively.

Now,

P+Q+R = 180° [Sum of angles of triangle]
➡ P + 100° + 45° = 180°

➡ P + 145° = 180°

➡ P = 180°- 145°

➡ P = 35°

•°• The measure of P = 35°

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HOPE IT HELPS!☺☺☺
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Answer 2

In the triangle PQR,

∠Q=100°

∠R=45°

by angle sum property,

∠P+∠Q+∠R = 180°

∠P+100°+45° = 180°

∠p = 180°-45°-100°

∠p =35°