Question

In ∆ PQR l (PQ) = 5.5 cm , m angle P= 50°, I(PR)=5cm then construct ∆ PQR.​

Answer 1

Answer:

∴ ∠PQR = 90°, and ∠P = ∠R

(opposite sides are equal)

∴∠P + ∠R = 90°

Hence ZP = ZR = \frac { 99\circ }{ 2 } = 45°

Steps of Construction:

(i) Draw a line segment QR = 5.5 cm

(ii) At Q, draw a ray making an angle of 90° and cut off QP = 5.5 cm.

(iii) Join PR.

∆PQR is an isosceles triangle.

(iv) Draw the angle bisector of ∠PQR. It is the line of symmetry. Since the triangle is an isosceles.

∴ It has only one line of symmetry.

Answer 2

Answer:

<PQR = ९०° and <P <R <p <r = ९०°