Question

In △PQR, <PQR= 480,<QPR=720,QO and RO are the bisectors of <PQR and

<PRQ, find <QOR pls help it's my exam​

Answer 1

Answer:

577 is the correct answer

Answer 2

Answer:

130° is right answer

Step-by-step explanation:

∠QPR=80°

∠PQR+∠QPR+∠QRP=180°

∠PQR+∠QRP=100°

2(x+y)=100°

x+y=50°

So, in △QOR

x+y+∠QOR=180°

∴∠QOR=180°−50°

=130°