Question

In ∆PQR, <Q=90 then prove that PQ²+QR²=PR².​

Answer 1

Answer:

proved

Step-by-step explanation:

if angle Q is 90 degree then it becomes a right triangles

so, by using phythagores theroem we can say

opposite square + adjacent square = hypotenuse square

PQ square + QR square = PR square

hence proved

Answer 2

In ∆PQR, <Q=90 then prove that PQ²+QR²=PR².