in ∆ pqr M and N are the midpoints of pq and pr respectively if the area of ∆PMN is 24 cm² find the area of ∆ pqr
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We have, PM = 15 cm,NR = 8 cm,PQ = 25 cm and PR = 20 cm Now, MQ = PQ - PM = 25 - 15 = 10 cm and PN = PR - NR = 20 - 8 = 12 cm Hence, PMMQ = 1510 = 32
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