In ∆PQR, m<Q=90° . Seg QM is perpendicular to side PR. PM =9, MR =25, then find QM. *
Answers
Answered by
2
Given : ∆PQR, m∠Q=90° . Seg QM is perpendicular to side PR.
PM =9, MR =25,
To find : QM
Solution:
∆PQR, m∠Q=90°
QM is perpendicular to side PR.
ΔPMQ and ΔQMR
∠MPQ = ∠MQR = 90° - ∠R
∠PMQ = ∠QMR = 90°
=> ΔPMQ ~ ΔQMR (AA)
=> PM/QM = QM/MR
=> PM * MR = QM²
=> 9 * 25 = QM²
=> 3² * 5² = QM²
=> 15² = QM²
=> 15 = QM
Hence QM = 15
Learn More:
Ratio of area of 2 similar triangles are 2:3. Area of the larger triangle is
brainly.in/question/7877543
if triangle abc- triangle def area of triangle abc is 64 square ...
brainly.in/question/14594418
Three triangles are marked out of a bigger triangle at the three ...
brainly.in/question/8018381
Similar questions