In ∆PQR, mQR = 6cm, mPR=2√2cm and angle PRQ=135°
Draw perpendicular from P to QR, to meet QR produced at S and find RS
(solve it using theorem)
(I will mark the correct answer as brainliest and give a 5 star vote)
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here we see that, 2 mol of Al produce 3 mole of H2
∴ 2 × 27 g of Al produce 3 × 2 g of H2 .
∴ 54 g of Al produce 6g of H2.
∴ 1 g of Al produce 6/54 = 1/9 g of H2.
∴ 0.15g of Al produce 0.15/9 g of H2
so,
number of mole of H2 produce = weight of HE produce/molar weight of H2
= (0.15/9)/2
= 0.15/18 = 0.00833 mol
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this is all i can do to help and if you can understand (b) part help me to plzz
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