Question

In ∆PQR of Fig. PQ = PR. Find the measures of ∠Q and ∠R.​

Answer 1

Step-by-step explanation:

It is an isosceles traingle.

So,

∠P +∠Q + ∠R.= 180°

30° + x + x = 180

2x = 180-30

$x = \frac{150}{2}$

$x = 75$

Therefore, ∠Q and ∠R = 75° each

30 +75+75=180°

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Answer 2

Answer:

angle Q = angle R - reason - angles opposite to equal sides are equal

hence by angle sum property of a trinagle

Angle P + Angle Q + Angle R = 180°

Angle P+ Angle Q + Angle P = 180° (since angle p = angle r )

2 x angle p + 30° = 180°

2 x angle p = 180° - 30°

2 x angle p= 150°

angle p = 150° /2

angle p = 75°

also, angle r = 75°