Math, asked by upendary1230, 14 days ago

In PQR p=2 Q and 2r=3 Q, calculate the angles of PQR. ​

Answers

Answered by Equuleus
1

Alright, this is a simple algebraic problem.

Given:

p = 2q

2r = 3q => r = 3q/2

So, as we know, by angle sum property, p + q + r = 180*

So,

2q + q + 3q/2 = 180*

4q/2 + 2q/2 + 3q/2 = 180

(4q + 2q + 3q)/2 = 180

9q/2 = 180

9q = 180*2

9q = 360

q = 360/9

q = 40

Now, knowing this value we can find the remaining values

p = 2q = 2*40 = 80*

q = 40*

r = 3q/2 = 3*40/2 = 120/2 = 60*

So, the three angles of PQR are p = 80*, q = 40* and r = 60*

Hope this Helped!

Stay safe, stay hydrated and stay sanitized!

ヾ(•ω•`)oヾ(•ω•`)o

Answered by sanskritijaiswal0503
2

Answer:

∠P = 80, ∠Q = 40, ∠R = 60

Step-by-step explanation:

In ΔPQR, ∠P = 2 *∠Q and, 2 *∠R = 3 *∠Q

We know that sum of three angles is 180 degree that is ∠P + ∠Q + ∠R = 180

∠Q = ∠P/2 -------(1)

And, ∠R = 3 *∠Q /2

     or, ∠R = 3 *∠P/4 ------(2)

Then, from the values of (1) and (2), ∠P + ∠P/2 + 3 *∠P/4 = 180  

                                                      Or, ∠P * (1 + 1/2 + 3/4) = 180  

                                                      Or, ∠P = 80

From (1), ∠Q = 40 and from (2) ∠R = 60.

Similar questions