Question

In ΔPQR, ∟P=2y0, ∟Q=y0, ∟R=600, the largest angle of ΔPQR is​

Answer 1

Solution:

In △PQR = 180°

∠P + ∠Q + ∠R = 180°

2y + y + 60° = 180°

3y + 60° = 180°

3y = 180° - 60°

3y = 120°

y = 40°


∠P = 2y = 2(40) = 80

∠Q = y = 40

∠R = 60

∠P + ∠Q + ∠R = 180°

80 + 40 + 60 = 180

Therefore:

The largest angle is ∠P which is 80°


Hope this will help.