In ∆PQR,√P=50°,√Q=85° then find√R.
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In triangle PQR
an.P=50°
an.Q=85°
Let an.R be x
an.P+an.Q+an.R=180°(angle sum property of triangle that says that sum of all interior angles are 180 degree)
50+85+x=180°
135+x=180°
x=45°=an.R
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