Question

in ∆ PQR , ∆ p= 70°,∆ Q=65° find ∆ R​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

Using the angle sum property of triangle

Angle A + Angle B + Angle C = 180°

So, therefore in Δ PQR =

Angle P + Angle Q + Angle R=180°

70° + 65° + Angle R = 180°

Angle R = 180°- 135°

Angle R = 45°

Thus, Angle R = 45°

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Answer 2

Answer:

GIVEN:

P=70°

Q= 65°

R= ??

SUM OF ALL ANGLES OF TRIANGLE =180°

Angle P + Angle Q+ Angle R = 180°

70° + 65° + Angle R =180°

135°+ Angle R = 180°

Angle R = 180°-135°

Angle R = 45°

Therefore,Angle R = 45°

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