In ∆PQR,∟ P=900 and ∟ R=300 ,find PR and QR if PQ=4cm.
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Step-by-step explanation:
In triangles PQS and PQR
∠P is common to both.
and ∠PSQ=∠PQR
Triangles PQS and PQR are equiangular
∴
PQ
PS
=
QR
QS
or, PS=
QR
PQ⋅QS
...(i)
Again, triangles QRS and PQR are equiangular
∴
QR
SR
=
PQ
QS
or, SR=
PQ
QS⋅QR
...(ii)
From eqns. (i) and (ii)
SR
PS
=
QR
PQ⋅QS
⋅
QR⋅QS
PQ
=
QR
2
PQ
2
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