in ∆ PQR, pm is a medium QR=8cm find pm ?
Answers
Answered by
1
Step-by-step explanation:
∠QPR=∠PMR=90°
∠PRQ=∠PRM(common)
ΔPQR=ΔMPR(AA similarity)
PR
QR
=
MR
PR
PR
2
=8∗4.5=36
PR=6cm
Similar questions