Question

In ∆PQR,point M is on the side PQ & point S is on the side PR such that QRSM is a trapezium.if MS:QR=3:5 then find area(∆PMS):area(trapezium QRSM).

Answer 1

MS:QR=3:5
So, QR:MS=5:3

So, ar(PQR):ar(PSM)=(QR:MS)^2
==>(ar(PSM)+ar(QRSM):ar(PSM)=25:9
==>1 + ar(QRSM):ar(PSM)=25:9
==>ar(QRSM)/ar(PSM)=25/9 - 1
==>ar(QRSM):ar(PSM)=16:9
So,
ar(PSM):ar(QRSM)=9:16

PLZ MARK IT AS BRAINLIEST.

Answer 2

Hope it helped you a lot....
All the best for your board exams........