In ∆PQR, Point S is the Midpoint of Side Qr. If PQ = 11, PR = 17, Ps =13, Find QR
Answers
Answered by
7
Step-by-step explanation:
Using Apollonius's theorem,
PQ
2
+PR
2
=2(PS
2
+SR
2
)
17
2
+11
2
=2(13
2
+SR
2
)
289+121=2(169+SR
2
)
410=2(169+SR
2
)
(169+SR
2
)=205
SR
2
=36
SR=6 cm
Since S is the midpoint of QR
QR=2×SR
QR=12
QR=12 cm.
Answered by
3
Step-by-step explanation:
Given that PQ=11 ,PS=13,PR=17
By Pythagoras theorem:
Here we get √17^2-13^2
∆PQR divides into two triangles ∆PSR and ∆PSQ
So we √120 +√120=2√120.
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