In ▲ PQR, point S is the midpoint of sideQR.if PQ =11,PR=17,PS=13 find QR.
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have you understand this figure now, since PS DIVIDES QR IN TWO EQUAL PARTS SO PS IS PERPENDICULAR TO QR NOW IN
TRIANGLE PQS USE PHYTHAGORUS THEOREM SIMILARLY FOR TRIANGLE PSR USE PHYTHAGORUS THEOREM THAT IS
(Hypotenuse)^2 = (Base)^2 + (Height)^2 for each of the triangle separately!
TRIANGLE PQS USE PHYTHAGORUS THEOREM SIMILARLY FOR TRIANGLE PSR USE PHYTHAGORUS THEOREM THAT IS
(Hypotenuse)^2 = (Base)^2 + (Height)^2 for each of the triangle separately!
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