Question

In PQR, PQ= 12cm and PR= 13cm, find tanP- cotR
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Answer 1

Answer:

0

Step-by-step explanation:

PR = 5

TanP = 5/12

CotR = 5/12

Tanp-CotR

=0

Answer 2

Answer:

Step-by-step explanation:

∆PQR,   PR2 = PQ2 + QR2  Pythagoras Theorem⇒QR2 = 132 - 122 = 169 - 144 = 25⇒QR = 5 cm

tan P = perpendicularbase = QR/PQ=5/12

cot R = baseperpendicular = QR/PQ=5/12

so, tan P − cot R = 5/12 −5/12 = 0

I HOPE IT IS HELPFUL