Math, asked by GautamPrabhu2329, 8 months ago

In ∆PQR,PQ=14 ,QR=7,PR=7√3,then the angle P =?

Answers

Answered by nandibuddhadev70

0

Step-by-step explanation:

QR square+PR square=(7)square +(7√3) square=49+147 =196

PQ square =(14) square=196
Pythagoras uppapadya
answer-90 digri

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