in PQR, PQ = 16 cm, Q = 90 and QR = 12 cm. Find the radius of the semicircle described on diameter PR and the area
of the figure
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Step-by-step explanation:
Area of circle with QR as diameter =2π(52)=225π cm2
Area of semi circle with diameter PR
=2π(42)=8π cm2
Area of semi circle with PQ diameter
=2π(32)=29π cm2
Area of triangle PQR=21×6×8=24 cm2
Area of shaded regions
=(8π+29π+24)−(225π)=12.5π+24−12.5π=24 cm2
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