Math, asked by satyavathisatyawati, 30 days ago

in∆ PQR,PQ^2 + QR^2 -PR^2 , then the right angle is at=_____________

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Answered by kshitija3183

0

Answer:

in∆ PQR,PQ^2 + QR^2 -PR^2 , then the right angle is at angle Q

Step-by-step explanation:

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