In ∆PQR,PQ =4 cm and QR=6 cm what can be the length of third side PR?
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Answered by
3
the answer could be solved by Pythagoras theorem if it would have been mentioned that the triangle is right angled if not then I'm Sry there is angle sum property but no side sum property.... it's a incomplete question
✔With Pythagoras theorem
H²=P²+B²
(PR²)=(PQ²)+(QR²)
PR²=(4²)+(6²)
PR²=16+36
PR²=52
by putting square root both sides
PR=7.21110....:-)
✔With Pythagoras theorem
H²=P²+B²
(PR²)=(PQ²)+(QR²)
PR²=(4²)+(6²)
PR²=16+36
PR²=52
by putting square root both sides
PR=7.21110....:-)
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Answered by
2
u want to use phythagarous theorm
(pr)2=(pq)2+(qr)2
(4)2+(6)2
=16+36
=52
so the third side of pr is √52
(pr)2=(pq)2+(qr)2
(4)2+(6)2
=16+36
=52
so the third side of pr is √52
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Why u have taken every where +2
sorry i understood
okk
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