Question

In ∆ PQR , PQ=4 cm , PS=4 cm and ∠P= 80 . Then the measurement of ∠Q is​

Answer 1

QR=3√5cm...

QS=2√5 cm

SR =5 cm...

Answer 2

GIVEN :-

• PQR is a ∆.
• PQ = 4 cm.
• PR = 4 cm.
• ∠P = 80°.

TO FIND :-

• The Value of ∠Q.

SOLUTION :-

Here in the question it is given that, in ∆PQR PQ = 4 cm , PS = 4 cm. Therefore as we know that a traingle having two equal sides is called " Isosceles Triangle". So as we know that in isosceles triangle [ Angle opposite to equal sides are equal ]

→ PQ = PR = 4 cm.

→ ∠R = ∠Q = x (say).

★ Now By the angle sum property in ∆OQR ★

→ ∠P + ∠Q + ∠R = 180°

→ x + x + 80° = 180°

→ 2x + 80° = 180°

→ 2x = 180° - 80°

→ 2x = 100°

→ x = 100°/2

→ x = 50°

Therefore,

• ∠R = ∠Q = x = 50°

HENCE THE REQUIRED VALUE FOR ∠Q IS 50°