Question

In ΔPQR, PQ=4cm, PR=8cm and RT=6cm. Find
(i) the area of ΔPQR
(ii) the lengthof QS.

Answer 1

Hi ,

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We know that ,

Area of triangle = ( base × corresponding altitude )/2

A = ( bh )/2 square units
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According to the problem given ,

In ∆PQR ,

PQ = b1 = 4 cm

PR = b2 = 8 cm

RT = h1 = 6cm

Let QS = h2 cm

i ) Area of ∆PQR = ( b1 × h1 )/2

= ( 4 × 6 )/2

= 12 cm²

ii ) Area of = 12 cm²

( b2 × h2 )/2 = 12

( 8 × h2 ) /2 = 12

h2 = ( 12 × 2 )/8

h2 = 3 cm

Therefore ,

Area of the triangle PQR = 12 cm²

QS = h2 = 3 cm

I hope this helps you.

: )