Question

In PQR,PQ=4cm,PR=8cm and RT=6cm.
Find
The area of PQR and the length of QS

Answer 1

Step-by-step explanation:

Area of triangle PQR=1/2×RT×PQ

=1/2×6×4

=12cm×cm

1/2×PQ×RT=1/2×PR×QS

PQ×RT=PR×QS

4×6=8×QS

QS=3cm

Answer 2

Area of ΔPQR and the length of QS is 12 cm² and 3 cm.

Step-by-step explanation:

Given in Δ PQR

PQ = 4 cm, PR = 8 cm , RT = 6 cm

Area of ΔPQR = $\frac{1}{2}$ × RT × PQ

                       = $\frac{1}{2}$ × 6 × 4

                        = 12 cm²

In ΔPQR , RT and QS are ⊥ on base of PQ and PR

$\frac{1}{2}$ × PQ × RT = $\frac{1}{2}$ × PR × QS

PQ × RT = PR × QS

4 × 6 = 8 × QS

QS = 3 cm

Hence area of ΔPQR and the length of QS is 12 cm² and 3 cm.