Question

In ∆PQR, PQ = 8 cm, QR = 15 cm. Find PR
(the triangle is right angled at Q).​

Answer 1

Answer:

17

Step-by-step explanation:

height=8cm

base= 15 cm

by pythogorus theorem:

PR^2=height^2+base^2

PR^2= 8^2 + 15^2

PR^2= 64+225

PR^2= 289

PR= root (289) { square moves to right side}

PR =17

Answer 2

Answer:

∆Q= 90°

PQ=8cm

QR=15cm

By PTM

(PR) 2= (PQ) 2+(QR)2

(PR) 2=(8cm)2+(15cm)2

(PR) 2=64+225

(PR) 2=289

PR=17 cm