Question

In ∆ PQR, PQ = PR & PA is the median. Which congruency

condition proves ∆ PQA ≅ ∆ PRA. pls answer fast​

Answer 1

Answer

We have,

According to given figure.

PQ=PR(giventhat)

QS=SR(Bydefinationofmidpoint)

PS=PS(Commonline)

Then,

ΔSPQ≅ΔSPR (BY congruency S.S.S.)

Hence, PS bisects ∠PQR by definition of angle bisector.

I hope you mate it will help you thank you

Answer 2

Answer:

IN Δ PQR

PQ = PR,,, PA is a median of Δ PQR that is A is midpoint of QR

•°• QA = RA ..........1

In Δ PQA & Δ PRA

PQ = PR ( Given)

QA = RA ( By above proved in equation 1 )

PA = PA ( common)

•°• Δ PQA = Δ PRA ( By S. S. S rule)