Question

In PQR, PQR = 30°, PRQ = 75° and QR = 8cm. Let us draw a rectangle equal in
area to that triangle.​

Answer 1

Step-by-step explanation:

1- let PQR be a triangle with QR= 8cm

2-At R draw a 75° angle

3-Draw xy // QR

4- At R draw Rt perpendicular to QR

5-join them and you will get the rectangle