Math, asked by lshrutibehere, 19 hours ago

In PQR, PQR = 900
. seg QS hypotenuse PR.
QS = 12cm, RS = 16cm, find PS

Answers

Answered by popatkhot1977

0

Answer:

PS = 9 cm

Step-by-step explanation:

In triangle PQR < pQR = 90

seg QS Perpendicular to hypotenuse

Here QS = 12 CM , RS = 16 CM , PS= ?

QS^2 = PS × SR

( 12)^2 = ps × 16

144 = ps × 16

144/ 16 = PS

9 = PS

ps = 9 cm

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