Question

In ∆PQR, ∠PQR = 90°, Seg QS ⊥ Seg PR.
PS = 10cm, SR = 8cm
Find QS and PQ. ​

Answer 1

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In ∆PQR, ∠PQR = 90°, Seg QS ⊥ Seg PR.

PS = 10cm, SR = 8cm

Find QS and PQ.

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We have using Pythagorus theorem,

QS2=PS.SR.. .. ..(1) [ Can be proved by applying Pythagorus theorem on the triangles ΔPQR, ΔPQS, ΔQSR]

Given PS=4,SR=9.

Then form (1) we have 

QS2=4×9

or, QS2=36

or, QS=6,

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