Question

In ∆PQR, ∠PQR = 90°, Seg QS ⊥ Seg PR.
PS = 10cm, SR = 8cm
Find QS and PQ. ​

Answer 1

Answer:

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Step-by-step explanation:

ΔPQR is right angled triangle where Q is right angle. QS ⊥ PR. QM bisect the ∠PQR. To prove: In ΔPQR,. QM bisector of ∠PQR.

Answer 2

Answer:

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