Question

 In ∆PQR , ∠ PQR = 90°and seg QS ⊥ hypotenuse PR, P-S-R,then *

A)〖PR〗^(2 )=PQ×PR

B) 〖QS〗^(2 )=PS×SR

C) 〖PR〗^(2 )=PQ×QR

D) 〖QS〗^(2 )=PQ×PR

​

Answer 1

Answer:

It's option b.

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