Question

In ∆PQR, ∠PQR = ∠PRQ and the bisectors of ∠PQR and ∠PRQ intersects at O such that ∠QOR = 120º. Show that ∆PQR is an equilateral triangle.​

Answer 1

Answer:

Step-by-step explanation:

∠QPR=80°

∠PQR+∠QPR+∠QRP=180°

∠PQR+∠QRP=100°

2(x+y)=100°

x+y=50°

So, in △QOR

x+y+∠QOR=180°

∴∠QOR=180°−50°

=130°

Answer 2

Answer:

∠QPR=80°

∠PQR+∠QPR+∠QRP=180°

∠PQR+∠QRP=100°

2(x+y)=100°

x+y=50°

So, in △QOR

x+y+∠QOR=180°

∴∠QOR=180°−50°

=130°

Step-by-step explanation:

f o l l ow me guys please