in pQr, pR =8cm ,LR= 4cm and pQ=6cm find1 the area of the pQr(2)QM
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In triangle PQR, PQ = 4 cm PR = 8 cm and RT = 6 cm
(i) Area of ∆PQR = 1/2 x Base x height = 1/2 x PQ x RT = 1/2 x 4 x 6 = 2 x 6 = 12 sq. cm
(ii) Area of ∆PQR = 12 sq. cm ⇒ 1/2 x PR x QS = 12 ⇒ 1/2 x 8 x QS = 12 ⇒ QS = (12 x 2)/8 = 3
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