Question

In ∆PQR, PS ⟂ QR and PS² = QS× RS. Prove that ∆PQR is a right angled triangle.
(class 10 CBSE SAMPLE PAPER 2017-18 MATHS)

Answer 1

[Figure is in the attachment]

SOLUTION:
In right angled ∆PSQ & ∆PSR

PQ²= PS²+QS²…………(1)

and PR²= PS²+SR²………(2)

On adding eq 1 & 2

PQ²+PR²= 2PS²+QS²+SR²

PQ²+PR²= 2(QS×SR) + QS²+SR²

[ GIVEN: PS²= QS×RS]

PQ²+PR²=(QS+SR)²

[a²+b²+2ab= (a+b)²]

PQ²+PR²=QR²        [ QR= QS+SR]

Hence,∆PQR is a right angled ∆ right angled at P.

HOPE THIS WILL HELP YOU…..

Answer 2

Answer:

sahi khel gaya

Step-by-step explanation:

OP I AGREE