In ∆PQR, PS⊥QR , ∠Q= ∠R and PQ=PR. By which congruency ∆PSQ ≅ ∆PSR
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Answer:
We have,
According to given figure.
PQ=PR(giventhat)
QS=SR(Bydefinationofmidpoint)
PS=PS(Commonline)
Then,
ΔSPQ≅ΔSPR (BY congruency S.S.S.)
Hence, PS bisects ∠PQR by definition of angle bisector.
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