Question

In ΔPQR, ∠Q=90ْ .Seg QM is median. PQ=6cm, QR=8cm. Find QM​

Answer 1

Answer:

MAY THIS WILL HELP U

Step-by-step explanation:

∠PQR = 90° (given)

:. By Pythagoras theorem

(PR)² = (RQ)² + (PQ)²

:. (PR)² = 8² + 6²

= 64 + 36

:. (PR)² = 100

:. (PR) =

$\sqrt{100}$

:. (PR) = 10

QM is median

:. M is mid point of PR

:. PM = 1/2 PR

:. PM = 1/2 × 10

:. PM = 10/2

:. PM = 5cm

∠PMQ = 90°

:. By Pythagoras theorem

(MQ)² = (PM)² + (PQ)²

= 5² + 6²

= 25 + 36

(MQ)² = 61

MQ =

$\sqrt{61}$

:. MQ = 30.5 cm