Question

in PQR Q=90° and sin P=3/5 then find the value of cos P
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Answer 1

Answer:

your answer will => 3/5

cos p = b/h

sin r = p/h

because pq will be base cos p and perpendicular for sir r

now by using the Pythagorean theorem.

Step-by-step explanation:

Answer 2

see here is your answer

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