In Δ PQR, ∠ Q=900
, If PQ:QR=1:1 , then PQ:PR=_______(1:2,1:√2,√2:1)
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Answer:
In △PQR,∠PQR=90°
BY Pythagoras theorem,
PR
2
=PQ
2
+QR
2
⇒(5)
2
=PQ
2
+(4)
2
⇒(5)
2
−(4)
2
=PQ
2
⇒PQ
2
=25−16
⇒PQ
2
=9
⇒PQ=
9
⇒PQ=3
tanR=
QR
PQ
=
4
3
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