Question

In Δ PQR, ∠ Q=900

, If PQ:QR=1:1 , then PQ:PR=_______(1:2,1:√2,√2:1)​

Answer 1

Answer:

In △PQR,∠PQR=90°

BY Pythagoras theorem,

PR

2

=PQ

2

+QR

2

⇒(5)

2

=PQ

2

+(4)

2

⇒(5)

2

−(4)

2

=PQ

2

⇒PQ

2

=25−16

⇒PQ

2

=9

⇒PQ=

9

⇒PQ=3

tanR=

QR

PQ

=

4

3

Step-by-step explanation:

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Answer 2

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