In ΔPQR , ∠ Q = 90° , ∠P = θ , PQ = 12 , QR = 5 find cos θ.
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In the pic it's clearly explained ,hope it helps...
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cos x = 12/13
in triangle PQR , ANGLE Q IS 90
THEN,
FROM PYTHAGORAS THEOREM
PR = 13
THEN.
COS X = PQ/PR = 12/13
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